Consider the low-speed flight of the space shuttle as it is nearing landing. If the air pressure and temperature on the nose of the shuttle are 1.2 atm and 300k respectively, what are the density and specific volume?© BrainMass Inc. brainmass.com December 24, 2021, 10:12 pm ad1c9bdddf
SOLUTION This solution is FREE courtesy of BrainMass!
If we assume that the air is a perfect gas, then we can use the ideal gas law.
P = rho*R*T
P is the pressure, rho is the density, R is the specific gas constant and T is the temperature.
If we use SI units, we must first convert the pressure to pascals.
1 atm = 1.013*10^5 Pa
P = 1.2 atm * 1.013*10^5 Pa/atm = 1.216*10^5 Pa
T = 300K
R = universal gas constant/ Molecular Weight = 287.058 J/(kg·K)
rho = P/(R*T) = 1.216*10^5 Pa/ (287.1 J/(kg*K) * 300 K ) = 1.412 kg/m^3
The specific volume is 1/rho
sv = 1/rho = 1/(1.412 kg/m^3) = 0.708 m^3/kg© BrainMass Inc. brainmass.com December 24, 2021, 10:12 pm ad1c9bdddf>