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Set of 7 problems on kinematics

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Please solve only the circled questions: 24, 30, 32, 42, 58, 68, 77. (Please see the attachment)

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24. a) Slope of the Position-Time graph at any instant gives the velocity at that instant. From the graph we see that the slop during segment B is maximum. Hence, speed during segment B is maximum.

b) Speed for segment A = Slope of segment A = 2/2 = 1 m/s (ignoring the -ve sign)

c) Speed for segment B = Slope of segment B = 2/1 = 2 m/s

d) Speed for segment C = Slope of segment C = 1/2 = 0.5 m/s (ignoring the -ve sign)

30. By definition, acceleration = change in velocity/Time*

* Time in which the change takes place

In the given problem :

Change in velocity = Final velocity - Initial velocity = 0 - 115 = -115 m/s.
Time = 13 sec.
Hence, acceleration = - 115/13 = - 8.85 m/s2 (due to ...

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