# Magnitude of acceleration and direction of acceleration of a particle

An 9.00 kg point mass and a 12.0 kg point mass are held in place 50.0 cm apart. A particle of mass (m) is released from a point between the two masses 20.0 cm from the 9.00 kg mass along the line connecting the two fixed masses.

a) Find the magnitude of the acceleration of the particle. (in m/s^2)

b) Find the direction of the acceleration of the particle. (either toward the 12 kg mass or the 9kg mass)

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#### Solution Preview

What we basically need to do is to first find the gravitational force of attraction between the particle and each of the masses using Newton's law of universal gravitation;

F=(G * m1 * m2) / r^2

where G= 6.67 * 10^-11 is the universal gravitational constant, m1 and m2 are the masses in attraction and r is there separation.

Now, to get the force of attraction between the ...

#### Solution Summary

The expert examines the magnitude of acceleration and direction of acceleration of a particle.