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force applied to the block and slab system

Please see attached file for full problem description.

A 4.40-kg block is placed on top of a 5.50-kg slab. If the slab is held fixed, the block can be made to slip only if a minimum force of 12.0 N is applied to it. The assembly is now placed on a horizontal, frictionless surface, as shown in the diagram.
a) What is the coefficient of static friction between the block and the slab?
b) What is the maximum horizontal force, F that can be applied to the slab so that the slab and the block will move together without relative slippage?
c) What acceleration of the system results if that force is applied?

Per teacher, there is no friction between the bottom one and the 5.50Kg, but there is friction between the 4.40 kg and the 5.50Kg.

4.40Kg

Force 5.50 Kg
---------->
floor

Extra credit continuation

d) Suppose a horizontal force were applied to the block rather than the slab what maximun force that can be applied without producing relative slippage between the block and slab?

e) What acceleration of the system results if that force is applied?

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Solution Summary

It finds the force and the acceleartoin of the block-slab system. The solution is detailed and has a '5/5' rating.

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