The liquid phase reactions
are carried out in a perfectly insulated CSTR. The desired reaction (a) is first order in A and zero order in B, while the undesired reaction (b) is zero order in A and first order in B. The feed rate is equimolar in A and B. Species A enters the reactor at a temperature of 100 deg C and species B enters at a temperature of 50 deg C. The operating temperature of the reactor is 400 K. The molar flow rate of A entering the reactor is
60 mol/min: CpA=20cal/(mol K), CpB=30cal/(mol K), CpD=50cal/(mol K), and
CpU=40cal/(mol K). CA0=0.01 M
for a: delta Hrxn = -3000 cal/mol of A at 300K
Ka= 1000e^-2000/T min^-1 where T is in K
For b: delta Hrxn = -5000 cal/mol of A at 300 K
Kb= 2000e^-3000/T Min^-1
1. What will be the exiting molar flow rate of C and D from the reactors?
2. What is the CSTR reactor volume for the conditions specified?
Flow rate and reactor volume for a Continuous Stirred Tank Reactor (CSTR) are calculated.
Continuous Stirred Tank Reactor and Plug Flow Reactor
Please see the attached file for the fully formatted problem(s).
1. Calculate the volume of a CSTR and of a PFR needed to convert 10 L/min of a 2.0 M solution of A to a concentration of 0.1 M. The reaction is A --> B, the rate law is -r = k CA, where k is 0.01667 sec-1. Which is larger? Why?
2. For the reaction given in problem 2, calculate (and graph on one graph) time versus CA/CA0 from 1 to 0.001 for a constant volume batch reactor.View Full Posting Details