Explore BrainMass

Explore BrainMass

    Finding Metal Removal Rate

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    In an electrochemical machining operation, the frontal working area of the electrode is 2.5in squared. The applied current=1500amps, and the voltage=12volts. The material being cut is pure aluminum, whose specific removal rate is 1.26 x 10^-4 in^3/amp-min.

    If the electrochemical machining process is 90 percent efficent, determine the rate of metal removal in in^3/hr.

    © BrainMass Inc. brainmass.com December 24, 2021, 6:55 pm ad1c9bdddf
    https://brainmass.com/engineering/mechanical-engineering/finding-metal-removal-rate-149355

    SOLUTION This solution is FREE courtesy of BrainMass!

    To express the rate of metal removal in terms of (in^3/hr) we calculate

    (the rate of metal removal) = (current)*(specific removal rate) * (minutes per hour) *(efficiency)

    = (1500amps)*(1.26 x 10^-4 in^3/amp-min) * (60 min / hr) * (90%/100%) =

    = 10.2 in^3/hr

    This is all the question asks now, so the voltage and working area are not needed, and this is the complete answer to your posting as it is written now.

    However, it may be that you forgot to add the question about the working gap, given the resistivity 6.2 ohm-in of the electrolyte, so, just in case, I give the answer to this question as well:

    the gap = (voltage)*(area) / [ (resistivity)*(current) ] = (12 V) * (2.5 in^2) / [ (6.2 ohm-in) * (1500 amps)] =

    = 0.0032 in

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 6:55 pm ad1c9bdddf>
    https://brainmass.com/engineering/mechanical-engineering/finding-metal-removal-rate-149355

    ADVERTISEMENT