A capacitor is used in the electronic flash unit of a camera. A small battery with a constant voltage of 6 V is used to charge the capacitor with a constant current of 10 microamperes. How long does it take to charge the capacitor when C = 10 microfarads? My Answer:
Final answer: 333.33 s
We know that charge, Q = current * time = I * t
Also, for a capacitor, C = ...
The answer with good explanation on why the student answered it wrongly.