Purchase Solution

Working with ripple voltage in diode circuit

Not what you're looking for?

Ask Custom Question

Determine the capacitance required in a half wave rectifier to produce a ripple voltage less than 0.2V. Assume that the input is a 60Hz signal with maximum voltage VM=100V and the load resistance R= 10kW.

I'm confused. What formulas do I use and how do I solve this?

Purchase this Solution
Solution Summary

Solution with all explanations and mathematical steps.

Solution Preview

We have Vdc = Vp = 100 V (max ac voltage)
<br>
<br>It is given that the load is 10KW (please verify whether it is
<br>10 K Ohm: If so, Idc = Vdc/R = 100/10*10^3 = 10*10^-3 A = 10mA)
<br>
<br>Assuming that it is 10 KW (power consumption of the ...

Purchase this Solution
Free BrainMass Quizzes
Air Pollution Control - Environmental Science

Working principle of ESP

Architectural History

This quiz is intended to test the basics of History of Architecture- foundation for all architectural courses.

View More Free Quizzes
Related BrainMass Solutions

  • Comment on Frankenstein power supply

    Further Voltage regulation is provided by the zener diode circuit.

  • DC power supply design

    Q1 solution: (a) The value of the peak-to-peak ripple voltage when the (full-wave) diode bridge rectifier is used can be estimated as follows: Vpp = I/(2*f*C), where Vpp is the peak-to-peak ripple voltage, I the DC current in the circuit, f the AC

  • Diodes and Path of Current

    If the voltage drops across each diode is 0.7V, what is the current through the resistor in each case? Finally, use the bridge circuit shown and design a DC power supply for a 12-V AC signal with a ripple voltage less than 0.4V.

  • Working with Zener diode voltage regulators.

    54727 Working with Zener diode voltage regulators. Please check my work and if incorrect give me the correct answer A shunt regulator utilizes a zener diode whose voltage is 5.1V at a current of 50 ma and whose incremental resistance is 8 ohms.

  • Graph source and load voltage of a circuit

    Diode blocks the current flow. So, there is no current flow in the circuit. In other words, the diode acts like an open circuit. Thus, the load voltage is .

  • Working with diodes and operational amplifiers

    (The small boxes are current limiting resistors; they prevent the current in the circuit from shooting to a high value, there by protecting the zener diode and LED) Q3.

  • Circuit Analysis with Sinusoidal Source Voltage

    42224 Circuit Analysis with Sinusoidal Source Voltage Consider the attached circuit. The sinusoidal source voltage is Vs(t)=20sin(2 pi t). The diode is ideal.

  • Electronic Principles

    Figure 5-3 represents the equivalent circuit of a voltage regulator where an unregulated 12V source is used to provide a stabilised voltage Vout using an 8V zener diode.

  • Diodes, transistors (including BJT) and current mirrors

    The series resistor presents the additional voltage drop with respect to diode current, wherein as the current through the diode increases at the conducting region, the total voltage across the diode also increases, as shown in the inclined section I-V

View More Related Solutions