The circuit shown in the attachment was built in the lab and v0 was measured to be 6.25 V. Verify this measurement using the voltage divider principle.
SOLUTION This solution is FREE courtesy of BrainMass!
total resistance in the circuit = (650Ohms+320Ohms+230Ohms) = 1200 ohms
Since a voltage of magnitude 24V is applied across this resistance, the current through the resistances =
= 24/1200 = 0.02 Amp
Thus the voltage across the 320 ohm resistor, V = I * R = 0.02*320 = 6.4 V -- answer
variation is the experimantal value is due to the variations in resistance values as they need not show the exact resistance always.© BrainMass Inc. brainmass.com September 28, 2022, 2:11 am ad1c9bdddf>