Explore BrainMass

# Working with a Voltage Divider

Not what you're looking for? Search our solutions OR ask your own Custom question.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

The circuit shown in the attachment was built in the lab and v0 was measured to be 6.25 V. Verify this measurement using the voltage divider principle.
Vo=320Ohms/(650Ohms+320Ohms+230Ohms)*24V=6.4V

© BrainMass Inc. brainmass.com September 28, 2022, 2:11 am ad1c9bdddf
https://brainmass.com/engineering/electrical-engineering/working-with-a-voltage-divider-37637

## SOLUTION This solution is FREE courtesy of BrainMass!

total resistance in the circuit = (650Ohms+320Ohms+230Ohms) = 1200 ohms

Since a voltage of magnitude 24V is applied across this resistance, the current through the resistances =

= 24/1200 = 0.02 Amp

Thus the voltage across the 320 ohm resistor, V = I * R = 0.02*320 = 6.4 V -- answer

variation is the experimantal value is due to the variations in resistance values as they need not show the exact resistance always.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

© BrainMass Inc. brainmass.com September 28, 2022, 2:11 am ad1c9bdddf>
https://brainmass.com/engineering/electrical-engineering/working-with-a-voltage-divider-37637