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    Working with a Voltage Divider

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    The circuit shown in the attachment was built in the lab and v0 was measured to be 6.25 V. Verify this measurement using the voltage divider principle.
    My Answer:
    Vo=320Ohms/(650Ohms+320Ohms+230Ohms)*24V=6.4V

    © BrainMass Inc. brainmass.com September 28, 2022, 2:11 am ad1c9bdddf
    https://brainmass.com/engineering/electrical-engineering/working-with-a-voltage-divider-37637

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    SOLUTION This solution is FREE courtesy of BrainMass!

    total resistance in the circuit = (650Ohms+320Ohms+230Ohms) = 1200 ohms

    Since a voltage of magnitude 24V is applied across this resistance, the current through the resistances =

    = 24/1200 = 0.02 Amp

    Thus the voltage across the 320 ohm resistor, V = I * R = 0.02*320 = 6.4 V -- answer

    variation is the experimantal value is due to the variations in resistance values as they need not show the exact resistance always.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com September 28, 2022, 2:11 am ad1c9bdddf>
    https://brainmass.com/engineering/electrical-engineering/working-with-a-voltage-divider-37637

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