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    Sampling and gausssian distribution

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    Assume, I have a Gaussian Distribution given by N~(u0,var) where u0 is mean and var is variance by sampling 999 points.

    I used Maximum Likelihood to get the above parameters i.e. u0 and var.

    Now from these 999 points, I take one point out (lets call it i) and add a new point (lets call it j). What will the new mean and variance be?

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    https://brainmass.com/engineering/electrical-engineering/sampling-gausssian-distribution-350767

    Solution Preview

    Definition of the mean (xm) of a number (n) of x(n) sample values is given by

    xm = 1/n*∑ {x(n)} (1) summed 1 to n

    Now if we take one sample with value (i) out then the new mean of n-1 samples will be

    xm = 1/(n-1)*∑ {x(n-1)} (2) summed 1 to n-1

    Where, by inspection between (1) & (2) the new sum is

    ∑{x(n-1)} = ∑{x(n)} - i (3) summed 1 to n-1 & 1 to n

    (3) in (2) gives

    ∑{x(n-1)} = 1/(n-1)*{∑{x(n)} - i} (4)

    If we then add in a new sample value (j) the new mean { Xm (new)} of (n) sample values will be

    xm (new) = 1/n*{∑{x(n)} - i + j} (5)

    xm (new) = (j - i)/n + 1/n*∑{x(n)} (5a)
    ...

    Solution Summary

    The maximum likelihood of parameter variances are provided.

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