Rayleigh PDF
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Show that the average (mean), mean-square, and median values of the Rayleigh PDF for amplitude are given by the equations listed in the attachment.
© BrainMass Inc. brainmass.com May 24, 2023, 1:32 pm ad1c9bdddfhttps://brainmass.com/engineering/electrical-engineering/rayleigh-pdf-25630
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p(A) = [A/A0^2]exp[-{A^2/2*A0^2}], A>= 0
1. Average (Mean)
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Integral (A=0 to infinity)[A*p(A) dA]
= (1/A0^2)*Integral (A=0 to infinity)[A^2exp{-(A^2/2*A0^2)} dA
Now from standard Integral table we get,
Integral (x=0 to infinity)[x^2exp{-(a*x^2)} dx = (1/4a)sqrt(pi/a)
Here a = ...
Solution Summary
The solution explains its steps as it performs the calculations to show that the average of the Rayleigh PDF amplitude is given by the listed equations.
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