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    Hydraulic Conductivity

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    A sample of drill core collected from an unconfined sandstone aquifer was tested using a constant head permeameter with a radius of 3cm at 20°C and provided the following data:

    Flow rate = 0.18 cm3/min
    Distance between manometers = 5 cm
    Difference in head between manometers = 2.8 cm

    A well in the same aquifer was pumped to a steady state, and the following information measured in a series of observation wells: (refer to attachments)

    - Calculate the hydraulic conductivity of the rock sample.

    - Use the data from the well pumping test to calculate the hydraulic conductivity of the aquifer as a whole.

    - Suggest possible reasons for the differences in the results of your two calculations, and discuss the relative advantages and disadvantages of field and laboratory permeability tests.

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    https://brainmass.com/earth-sciences/groundwater/hydraulic-conductivity-509870

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    Calculate the hydraulic conductivity of the rock sample.
    _________________________________________________
    (1) Q=KiA
    Q= flow rate, K= hydraulic conductivity, i= hydraulic gradient = change in hydraulic head/change in distance, A = cross sectional areas
    (2) A= r^2pi
    Thus,
    A = (3 cm)^2 x pi = 28.27 cm^2
    rearranging equation (1), isolate for K, hydraulic conductivity
    (3) K = Q/iA
    K = 0.18 cm3/min / (2.8cm/5cm)*28.27 cm^2
    K = 0.0114 cm/min

    Use the data from the well pumping test to calculate the hydraulic conductivity of the ...

    Solution Summary

    The distances between manometers for hydraulic conductivity is examined.

    $2.19