Purchase Solution

Sin

Not what you're looking for?

Ask Custom Question

Christian beliefs:
What is the basic human problem, what is its cause, and what is its solution? Ideas are generated.

Purchase this Solution
Solution Summary

This solution the nature of sin in Christianity is contemplated in the context of religious studies.

Solution Preview

Man's basic problem is sin. It is not so easy to define its cause. If we go back to the Garden of Eden, we see that the cause of sin was rejection of the "tree of life." This is symbolic of the way of life defined by the Creator, known as the "Torah" in Jewish thought. Adam and Eve were told they were free to eat of the tree (only forbidden to eat from the tree of the knowledge of good and evil), but they didn't eat from the tree of life. This was the opportunity for Satan to come in and entice the woman to eat from the forbidden fruit of the tree of the knowledge of good and evil. Of course, she ate ...

Purchase this Solution
Free BrainMass Quizzes
Bible Verse Knowledge

Do you know where these famous biblical verses are found? Test your verse knowledge with this quiz.

Old Testament Scriptures

Do you know where to find famous passages in the old testament? Test your knowledge with this quiz.

The Bible Part 2

Ready to keep testing your knowledge of the order of the books of the Bible? Find out how much you know with this quiz.

Biblical Numbers

Do you know the important numbers found in the Bible?

Biblical Locations

Find out how much you know about where things happened in the Bible with this quiz.

View More Free Quizzes
Related BrainMass Solutions

  • Proof of a Trigonometric Identity

    x) / (2 sin x cos x) [Because sin^2 x + cos^2 x = 1] = 2 (1 + sin x cos x + cos x + sin x) / (2 sin x cos x) = (1 + sin x cos x + cos x + sin x) / (sin x cos x) = 1/sin x cos x + (sin x cos x / sin x cos x) + cos x / sin x cos x + sin x / sin x

  • Gaussian Curvature of the Unit Sphere

    + sin^2 u = 1, F = r_u . r_v = -sin u cos u sin v cos v + sin u cos u sin v cos v = 0, G = r_v . r_v = sin^2 u (sin^2 v + cos^2 v) = sin^2 u.

  • Trigonometry

    [Please check again at your end.] 2) Derive the identity for sin 3x in terms of sin x sin 3x = sin(x + 2x) = sin x cos 2x + cos x sin 2x = sin x (1 - 2 sin^2 x) + cos x (2 sin x cos x) = sin x - 2 sin^3 x + 2 sin x cos^2 x = sin x - 2

  • Math Equations

    sin^4 (x) + cos^4 (x) = (sin^2 x)^2 + (cos^2 x)^2 + 2 . sin^2 x . cos^2 x - 2 . sin^2 x . cos^2 x = (sin^2 x + cos^2 x)^2 - 2 . sin^2 x . cos^2 x = 1 - 2 . sin^2 x . cos^2 x = 1 - 2 . sin^2 x . (1 - sin^2 x ) = 1 - 2 . sin^2 x + 2 sin^4

  • Trigonometric expressions

    Numerator: Sin 3 x - 3 Sin x Sin (x+y) = Sin x Cos y + Sin y Cos x Cos (x+y) = Cos x Cos y - Sin x Sin y Therefore Sin 3x = Sin (2x+x) = Sin 2x Cos x + Cos 2x Sin x Sin 2 x =Sin x Cos x + Sin x Cos x = 2 Sin x Cos x

  • How do you find by the method of summation the value of the integral os sin(x) and cos(x)?

    = 2 .1. sin { (b-a)/2}.cos {(b+a)/2} = sin [ {(b-a)/2} + {(b+a)/2}] + sin [{(b-a)/2} - {(b+a)/2}] = sin b + sin ( - a )

  • Trigonometry

    . 2- Solution Sin 2x = cos x sin 2x - cos x = 0 2 sin x cos x - cos x = 0 [sin 2x = 2 sin x cos x] cos x ( 2 sin x - 1) = 0 cos x = 0 and 2 sin x - 1 = 0 x = 90 degrees and 2 sin x = 1 & x = 270 degrees sin

  • Spherical Polar Coordinates Confirmation

    z = r cos   g ( x , y , z ) = r cos  + r sinsin Φ - r 2 sin  cos Φ sinsin Φ = r cos  + r sinsin Φ - r 2 sin 2  cos Φ sin Φ Now

  • Graphically Analysis Trigonometric Functions

    If it could, prove that it is. 5. sin^4 t - cos^4 t = 2 sin² t -1 ans. - sin^4t - cos^4 t = (sin²2t - cos²t) (sin²t + cos²t) = (sin²t-(1-sin²t)) (1) = 2 sin²t - 1 6. 1 + 2 cos²t + cos^4t = sin^4t ans.?

  • Calculus - Integration

    Method 1: Let I =  sin^2 q dq Let sin^2 q = u and dx = dv  u dv = uv -  v du I = (sin^2 q )(q) -  (q)(2 sin q cos q) dq = q sin^2 q -  (q)(sin 2q) dq = q sin^2 q - [(q)(- cos 2q /2) -  (- cos 2q /2) dq ] = q sin^2 q + (1/2) q cos 2q - (1/

View More Related Solutions