# Working with Velocity, Displacement and Time of Travel

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A body which is uniformly accelerated, changes its velocity from 36km/h in one direction to 18km/h in the opposite direction in 6 seconds. Find the total distance traveled in that time.

Â© BrainMass Inc. brainmass.com December 24, 2021, 4:47 pm ad1c9bdddfhttps://brainmass.com/physics/work/working-velocity-displacement-time-travel-7475

## SOLUTION This solution is **FREE** courtesy of BrainMass!

Initial velocity u = 36km/h = 36 x (5/18) m/s (say, to the right)

Velocity after 6 second = 18 x (5/18) m/s to the left.

Using V = u + at ......(1)

-5 = 10 + a x 6

6a = -15 or a = -2.5 m/s^2

Let the distance traveled to the right be S1.

V^2 = U^2 + 2 a S1 .......(2)

0 = 10^2 + 2 (-2.5) S1

Or, S1 = 20 m

Let the distance traveled to the left be S2

Similar to eqn(2) we can write,

5^2 = 2 x 2.5 x S2

Or, S2 = 5 m

Therefore the total distance = 20+5 = 25m (Ans)

Â© BrainMass Inc. brainmass.com December 24, 2021, 4:47 pm ad1c9bdddf>https://brainmass.com/physics/work/working-velocity-displacement-time-travel-7475