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    Working with Velocity, Displacement and Time of Travel

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    A body which is uniformly accelerated, changes its velocity from 36km/h in one direction to 18km/h in the opposite direction in 6 seconds. Find the total distance traveled in that time.

    © BrainMass Inc. brainmass.com December 24, 2021, 4:47 pm ad1c9bdddf
    https://brainmass.com/physics/work/working-velocity-displacement-time-travel-7475

    SOLUTION This solution is FREE courtesy of BrainMass!

    Initial velocity u = 36km/h = 36 x (5/18) m/s (say, to the right)

    Velocity after 6 second = 18 x (5/18) m/s to the left.

    Using V = u + at ......(1)

    -5 = 10 + a x 6

    6a = -15 or a = -2.5 m/s^2

    Let the distance traveled to the right be S1.

    V^2 = U^2 + 2 a S1 .......(2)

    0 = 10^2 + 2 (-2.5) S1

    Or, S1 = 20 m

    Let the distance traveled to the left be S2

    Similar to eqn(2) we can write,

    5^2 = 2 x 2.5 x S2

    Or, S2 = 5 m

    Therefore the total distance = 20+5 = 25m (Ans)

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 4:47 pm ad1c9bdddf>
    https://brainmass.com/physics/work/working-velocity-displacement-time-travel-7475

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