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When 2 objects w/ a difference in time will become equal

A television is dropped from the top of a cliff, and 1 second later a second television is thrown downward with a velocity of 20 m/s. How far below the cliff will the second television overtake the first?

Could you please show me the detailed work (with the equations) of how to achieve the answer. Our teacher gave us the answer but no work!

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Note that the distance between two TVs after 1 second of the first TV dropped is equal to
d=(1/2)g*t^2=(1/2)*g*1^2=4.9 (m)

Assume that after T seconds the second TV catches the first TV. We have


Solution Summary

A question in classical mechanics is answered.