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Motion of particle

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A particle of mass m moves under a force F = -c(x^3), where c is a positive constant. Find the potential energy function. If the particle starts from rest at x = -a, what is its velocity when it reaches x = 0? Where in the subsequent motion does it instantaneously come to rest?

Answer:V=1/4(cx^4); [Sqrt. (c/2m)](a^2); x = +-a

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Solution Summary

This solution shows step-by-step calculations to determine where the particles in motion comes into rest.

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