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Frictional Retarding Force

A worker does 300 J of work against a frictional retarding force of 15 N in pushing a power sweeper across a floor in 3.0 Seconds. If the sweeper moves with a constant speed, how fast is it going? I believe the answer is 6.7 m/s. I need to see each step and formula to solve this question.

Solution Summary

This solution contains step-by-step calculations determine the constant speed by using the distance, work and force.