1)/2)/3) I have the Mag field B, the charge q, and the velocity v.
To find the force I cross q*v with B.

4)I have the current I, the Mag field B, with the field in the x-z plane. I find the force using B = F/(I*l)?

5)I have the area A, length l, voltage V, resistivity (rho)and Mag field B.
R = (rho)*l/A. I can find the torque by t = uXB or t = NIAB. Do I manipulate some variables to find the number of loops based off the Area and length?

6) I have the velocity v, radius r, charge q, and mass m. I can find the strength of the Mag Field using qvB=mv^2/r

7)Not sure how to use the number of turns to find the current here...

Force will act only on portion of segment along - x axis. Portion of wire 7.2 m long parallel to the magnetic field will have no force acting on it. Net force is the force which is acting on segment that is 6.0 m along - x axis.

F = BiL sinx ( x = 90 degree, B is along positive z axis and L is parallel to x ...

Solution Summary

The solution examines the magnetic fields and forces.

Force on a current carrying conductor due to magnetic field. ... The force on a current carrying wire due to external magnetic field is given by the formula. ...

... All frictional forces are negligible ... rails, the voltage source and the crossbar can be taken to have constant value, R. A constant uniform magnetic field B acts ...

... B) Also same question, however magnetic force is required to reverse the direction of the magnetic field from saturation in the positive direction in the ...

... and b = 4 m, determine I1 and I3 so that the total magnetostatic force on I ... Net magnetic field at the centre O is the vector sum of the magnetic fields due to ...

... In the above diagram, the force vector is shown perpendicular to the plane containing the magnetic field (along Z-axis) and the velocity vector (in space ...