A circus acrobat of mass M leaps straight up with initial velocity v(initial) from a trampoline. As he rises up, he takes a trained monkey of mass m off a perch at a height "h" above the trampoline. What is the maximum height attained by the pair?
Using conservation of energy it follows that the velocity as a function of height, v(x), satisfies the equation:
1/2 v(x)^2 = 1/2 v(0)^2 - g x (1)
To find the velocity after the height h is reached use conservation of momentum. Let's denote velocities after ...
A detailed solution involving conservation of momentum and basic kinematics is given.