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The Conservation of Angular Momentum and Final Angular Velocity

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SEE ATTACHMENT #1 for diagram of before and after rearrangement.

A framework consists of two thin, uniform bars of mass M= 12 kg, length L= 3 m, and two thin, uniform bars of mass m= 6 kg, length D= 3 m, forming a rectangle of length L width D. It is rotating in space with initial angular velocity Wo= 18 rad/sec.
At some instant, one corner breaks loose and the bars rearrange into a straight line rotating about a c.m. axis at angular velocity Wf.

Find the final angular velocity.

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Solution Summary

The conservation of angular momentum and final angular velocity are determined. In a step by step process, the solution is explained in good detail.

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The law which applies here is the conservation of angular momentum, 'Io Wo=If Wf.
You will need to recall that the moment of inertia about a c.m. axis of any thin, uniform rod of mass M, length L, is: (1) (1/12)(M)( L^2), and the translation of axis theorem is (2) Ip = Io + M h^2 in which 'h' is the ...

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