A 0.144 kg baseball is pitched horizontally at 32.0 m/s. After it is hit by the bat, it moves at the same speed, but in the opposite direction.
(a) What was the change in momentum of the ball?
-9.22 kg·m/s *correct
(b) What was the impulse delivered by the bat?
-9.22 N·s *correct
(c) If the bat and ball were in contact for 0.75 ms, what was the average force the bat exerted on the ball? (in newtons)
* I tried saying that F(delta t)= (delta p) meaning that F= -9.22/.75 giving me F= -12.29. I have tried that and 12.29 with no success.
All equations are correct.
However, the unit of the time is off by ...
It shows how to calculate the avearge force exerted on the baseball by the bat.
Force on baseball after being hit
Estimate the force on a 145-gram baseball if it hits the bat at 50 miles per hour and stays in contact with the bat for 0.1 second, during which time it reverses direction and leaves the bat at 75 miles per hour.
Express the result in newtons and in pounds and explain your answer.View Full Posting Details