The vector A has a magnitude of 6m and vector B has magnitude of 4 m. That is the angle between them if the magnitude of the resultant is (a) 3m (b) 8m?
Let vector A lie along the x-axis. Do each part graphically and by components.
If we have two vectors A and B at an angle theta, then the resultant is given by the formula,
R^2 = A^2 + B^2 + 2 AB Cos(theta)
For the first case, R^2 = 9
9 = 36 + ...
This solution provides a quick explanation for finding the angels between vectors. It uses two attached .gif files to enhance understanding.