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Angle between two vectors

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The vector A has a magnitude of 6m and vector B has magnitude of 4 m. That is the angle between them if the magnitude of the resultant is (a) 3m (b) 8m?
Let vector A lie along the x-axis. Do each part graphically and by components.

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This solution provides a quick explanation for finding the angels between vectors. It uses two attached .gif files to enhance understanding.

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If we have two vectors A and B at an angle theta, then the resultant is given by the formula,

R^2 = A^2 + B^2 + 2 AB Cos(theta)

For the first case, R^2 = 9

9 = 36 + ...

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