I only need the last five parts explained to me.
See attached PDF file for the question !
Due date: Mon 22 Mar 2004 09:00:00 AM MST
Pulling Out Tree Stump
You are in a truck trying to pull out a tree stump. The mass
of the tree stump m is 170.0 kg. You have attached the winch
at the front of the truck to the tree as shown in the diagram
As you try to pull out the stump with the truck, the winch ex-
erts a time dependant force with magnitude: Fws(t) = F0ebt
where F0 and b are constants, and t is the time since the
winch began pulling. If the force necessary to remove the
trunk is Fout, how long will it take to pull out the stump?
Use the following values in your calculation: F0 = 20.0 N
b = 4.1 s��1
Fout = 17000.0 N
= 51.0 degrees
You are correct. Your receipt is 480-1079
Find the work done on the stump from the time that you
start pulling the stump with the truck until the time that the
stump comes out from the ground.
Also, nd the power delivered to the stump at half the time
from when the truck starts to pull to when the stump breaks
Once the stump breaks free, all horizontal forces on the stump
except the force from the cable are negligible for a time, and
the force from the wire as a function of position becomes:
Fws(x) = Fout
8 [1+7e��cx] where Fout is the same as above, c is
a constant, and x is the distance that the stump has traveled.
After you pull out the stump, you drag it a horizontal distance
x1 with the truck. Find the work done on the stump by the
winch from when it started moving until it reaches a distance
x1. The stump does not come o the ground during this
time, and the angle doesn't change. Use the following values
in your calculation: c = 7.0 m��1
x1 = 3.9 m
= 51.0 degrees W1 =
Find the speed of the stump when it is at position x1. Re-
member, all horizontal forces on the stump are negligible ex-
cept the force from the cable until after the stump has traveled
What is the power being delivered to the stump by the cable
when it is at the position x1?
1. Force on the block F = F(t)Cos(90-51) = 0.777 F(t)
The block will come out when the force F(t) reaches Fout = 17000 N
We will write, 17000 N = 0.777 * Fo Exp(bt)
Or, Exp(bt) = 17000/(0.777*20) where b = 4.1/sec
exp(4.1 t) = 1093.95
or, 4.1 t = ln(1093.95)
===> t = 6.997/4.1 = 1.7 Sec ---Answer
2. Workdone = force x displacement
Also work done = change in Kinetic enegy of the stump
If we know the force as a function of time, then we can get the velocity of the mass after a time t from Newton's law.
m dv/dt = F(t)
dv = (1/m) F(t)dt
V = integral from time t=o to t=1.7 of this value
= (1/m) int(0 to 1.7) 0.777 ...
Solution gives all mathematical steps.