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Force between two point charges

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Factor of k for air is 8.93x10(power)9 Nm(power)2/C(power)2

Calculate force between charges of +150.0(micro)C and
-75.0(micro)C that are 0.600 m apart in air.

* I am not able to use the proper symbols for (power), or (micro)

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Solution Summary

The expert calculates the force between two opposite charges.

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You are given with two charges one is + and the other is -ve. Thus the nature of the force is attractive. It is given by,

F = k (q1 x q2)/distance square

here ...

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