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    Periodic Motion of a Mass on a Spring

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    The position of a mass on a spring is given by x = (6.5 cm) cos [2 pi t/ (0.88s)]. (a) What is the period of this motion? (b) Where is the mass at t = 0.25 s? (c) Show that the mass is at the same location at 0.25 s + T seconds as it is at 0.25 s.

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    Solution Preview

    The standard equation for simple harmonic motion is
    x = A cos [2 pi t / T]
    where x is position, A is amplitude, t is time, and T is period.

    (a) matching the equation in the problem to the standard equation, we see immediately that the period is 0.88s.

    (b) ...

    Solution Summary

    Solution shows the equation for simple harmonic motion and proceeds step-by-step for a complete solution of all the parts of the question. Solution also shows how to use radians and degrees.

    $2.49

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