In a simple electric circuit, Ohm's law states that V=IR, where V is the voltage in volts, I is the current in amperes and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.01 volts per second and, as the resistor heats up, the resistance is increasing at 0.03 ohms per second. When the resistance is 300 ohms and the current is 0.02 amperes, at what rate is the current changing?
___ amperes per second
The rate of change of current is found given change in voltage and resistance.