Newton's laws of motion and friction
The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.48 with the floor. If the train is initially moving at a speed of 52 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?
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Question
The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.48 with the floor. If the train is initially moving at a speed of 52 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?
Solution:
Initial speed of railroad car u = 52 km/h
= 52(5/18) m/s
= 14.44 ...
Solution Summary
The solution calculates the minimum distance covered by a railroad car without sliding the crates in it.