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# Find friction coefficient such that block m does not slip.

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On a frictionless table a block of mass M=1.75 kg is attached to a spring of negligible mass whose force constant k= 60 nt/m. Riding on top of M but not attached to it, is a block m= .65 kg. The blocks execute SHM with amplitude Xm= .25 m.
Find the minimum value of the coefficient of friction, u, between the two blocks, such that m remains in place. See ATTACHMENT for a diagram with parameters .

https://brainmass.com/physics/newtons-second-law/find-friction-coefficient-block-not-slip-20062

#### Solution Preview

SOLUTION
Physics statements:
A. The general equation for x(t) of a body executing SHM with amplitude Xm, angular frequency w, and initial phase angle Q, is:
(1) x= Xm cos (w t + Q)
B. A total mass 'm + M' driven by a spring with force constant 'k', executes SHM with a period given by:
(2) T= (2 Pi) ...

#### Solution Summary

The expert finds the friction coefficient such that block m does not slip. A diagram with parameters are provided.

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