A 4.0 N force acts for 3.0 s on an object. The force suddenly increases to 15 N and acts for one more second. What impulse was imparted by these forces to the object?
Please provide detailed explanation
SOLUTION This solution is FREE courtesy of BrainMass!
Impulse(I) = Force(F) * Time(t)
I1 = F1*t1 = 4N*3s = 12 N-s
I2 = F2*t2 = 15N*1s = 15 N-s
Total impulse imparted by these forces to the object, I = I1+I2 = (12+15) N-s = 27 N-s© BrainMass Inc. brainmass.com December 24, 2021, 10:17 pm ad1c9bdddf>