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    A 4.0 N force acts for 3.0 s on an object. The force suddenly increases to 15 N and acts for one more second. What impulse was imparted by these forces to the object?
    Please provide detailed explanation

    © BrainMass Inc. brainmass.com December 24, 2021, 10:17 pm ad1c9bdddf
    https://brainmass.com/physics/newtons-laws/impulse-force-459688

    SOLUTION This solution is FREE courtesy of BrainMass!

    Impulse(I) = Force(F) * Time(t)

    I1 = F1*t1 = 4N*3s = 12 N-s
    I2 = F2*t2 = 15N*1s = 15 N-s

    Total impulse imparted by these forces to the object, I = I1+I2 = (12+15) N-s = 27 N-s

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 10:17 pm ad1c9bdddf>
    https://brainmass.com/physics/newtons-laws/impulse-force-459688

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