(a) According to Rayleigh's criterion, what is the intrinsic angular resolution of these binoculars? Assume that the light have a wavelength of 500 nm.
(b) At best, the pupil of your eye has an aperture of 7.0 mm diameter. Compare the angular resolution of your eye divided by a factor of 7.0 with the intrinsic angular resolution of the binoculars. Which of the two numbers determines the actual angular resolution you can achieve while looking through the binoculars.
2. A Newton's ring apparatus consists of a lens with one flat surface and one convex surface rests on a flat plate of glass (Fig. 35-45a). A light ray normally incident on the lens will be partially reflected by the curved surface of the lens and partially reflected by the flat plate of glass. The interference between these reflected rays will be constructive or destructive, depending on the height of the air gap between the lens and the plate. The interference gives rise to the pattern of Newton's rings, shown in Fig. 35-45b.
(a) Why is the center of the pattern dark?
(b) Show that the radius of the mth dark ring is r= √(mλR-m^2 λ^2/4) where λ is the wavelength of the light and R is the radius of curvature of the convex surface of the lens.
(c) What is the radius of the first dark ring if λ= 500 nm and R = 3.0 m?
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The solution discusses the answers the given questions regarding light and interference.
Reflected Light and Interference Problems
Two Glass Plates (see attached file)
Two glass plates are separated by fine wires, with diameters d1 = 0.0510 mm and d2 = 0.0530 mm, as indicated in the figure below. The wires are parallel and separated by a distance of L = 6.89 cm. If monochromatic light with lamba = 577 nm is incident from above, what is the distance (in cm) between adjacent dark bands in the reflected light? (Consider interference only between light reflected from the bottom surface of the upper plate and light reflected from the upper surface of the lower plate.)View Full Posting Details