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Double slit interference and circular aperture diffraction


(a) A double slit experiment is performed with 589 nm light and slits-to-screen distance of 2.00 nm. The tenth interference minimum is observed 7.26 mm from the central maximum. Determine the spacing of the slits.

(b) If the slit is replaced by a circular aperture with a diameter equal to the spacing of the double slit, find the width of the central maximum of the resulting pattern on the screen.


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Path difference between two rays = d sin @. For destructive ...

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