Impedance of a circuit; Fendt, Combinations of resistors
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Find impedance of the circuit below. R1 = 10 Ω, C= 100mF
E=10VAC
60Hz
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Solution Summary
Impedance of a circuit, Fendt, and combinations of s resistor are examined.
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Find impedance of the circuit below. R1 = 10 Ω, C= 100mF
IR
I IC
Solution: Reactance of the capacitor = XC = 1/jωC = 1/j(2ПfC) where f = frequency = 60 Hz
Substituting values: XC = 1/j(2Пx60x100x10-3) = 1/j37.7 ohm
Let equivalent impedance of the parallel combination of the resistance and capacitance be Z. Then, 1/Z = 1/R1 + 1/XC = 1/10 + j37.7 = 0.1 + j37.7 = √(0.12 + 37.72)/tan-1(37.7/0.1)
1/Z = 37.7/89.85O
Z = (1/37.7)/-89.85O = 0.0265/-89.85O ohm
Impedance can also be expressed as: Z = 0.0265cos(-89.85O) + j0.0265sin(-89.85O) = 0.0000693 - j0.0265
Z ≈ - j0.0265 ohm
1. Find the voltages (V1 and V2) and current (A) across the following sets of series circuits (see figure above) where the voltage source is 12 VDC.
a. R1=50Ω, R2=100Ω
b. R1=100Ω, R2=200Ω
c. R1=200Ω, R2=400Ω
Solution: As R1 and R2 are in series, net resistance in the circuit R ...
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