The illumination, I in luxes of a surface d meters from a lightsource given by I=kd^(-2) where k is a constant based on the intensity of the light source.
(a. Solve for k if we know that I = 750 luxes at a distance of 2 meters from the light source. k = 3000)
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B. IF OUR SOLAR POWERED CALCULATOR NEEDS AT LEAST 300 LUXES TO OPERATE, HOW FAR AWAY FROM THE LIGHT SOURCE CAN WE PLACE THE CALCULATOR AND STILL BE ABLE TO OPERATE IT?