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Intensity of Light and Distance from Source

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The illumination, I in luxes of a surface d meters from a light source given by I=kd^(-2) where k is a constant based on the intensity of the light source.

(a. Solve for k if we know that I = 750 luxes at a distance of 2 meters from the light source. k = 3000)

This is the question I need help with!!
B. IF OUR SOLAR POWERED CALCULATOR NEEDS AT LEAST 300 LUXES TO OPERATE, HOW FAR AWAY FROM THE LIGHT SOURCE CAN WE PLACE THE CALCULATOR AND STILL BE ABLE TO OPERATE IT?

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Solution Summary

The Intensity of Light and its relationship to Distance from Source is calculated.

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