Questions of Fluid Mechanics
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A sailboat is moving in the "y" direction. The wind approaches the boat at an angle of 45 degrees to the "y" direction and is turned by the sails such that it leaves in exactly the minus "y" direction.
A) If we assume that the average velocity of the incoming and outgoing wind is 10 m/s and that the mass flow rate of air being turned by the boats sail is 200 kg/s, what are the "x" direction and "y" direction components of the force exerted by the boat's sail on the air?
B) There are the opposite of the forces exerted by the air on the boat. The "y" component of the wind force drives the boat in its direction of travel. What does the "x" component do?
(See attached file for full problem description)
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Solution Summary
This solution involves step-by-step calculations for finding the value of force.
Solution Preview
A). The force exerted by the sail on the air is:
10 m/s * 200 kg/s = ...
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