Faraday's Law of Electrolysis
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How much time would it take to deposit 115 g of copper from a copper sulfate solution using a 3.75 Amp current? Assuming optimum conditions and calculating theoretical time.
m = 115g Cu
F = Faraday's constant = 96,500 C mol ^-1
M = for Cu 63.55 g mol -1
Z = 2e-per atom for copper = 2
I = 3.75 A = 2.5C/s
t=x
Faraday's equation
m=[(I.t)/F].(M/z)
t =m.F.z/I.M
I get
t= (115g Cu x 96,500 C/mol X 2)/(3.75C/s x 63.55 g Cu/mol)
= (115 x 96,500 x 2 )/(3.75/s) x 63.55
= 1379 mins
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The expert examines Faraday's law of electrolysis.
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