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    Simple Harmonic Motion

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    A 165 g mass attached to a horizontal spring oscillates at a frequency of 2.80 Hz. At t=0 seconds, the mass is at x=5.20 cm and has v_x = -42.0 cm/s. Determine:

    A) The period in seconds
    B) The angular frequency is rad/s
    C) The amplitude in meters
    D) The phase constant in rad
    E) The maximum speed in m/s
    F) The maximum acceleration in m/s^2
    G) The total energy in J
    H) The position at t=4.80 s in meters

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    https://brainmass.com/physics/energy/simple-harmonic-motion-springs-29867

    Solution Preview

    x(t) = Acos(wt+phi)
    v(t) = dx(t)/dt = -wAsin(wt+phi)
    a(t) = dv(t)/dt = -w2Acos(wt+phi) = -w2x.

    f= 2.8 hz

    A) The period in seconds

    period= T=1/f= 0.3571 seconds

    B) The angular frequency is rad/s

    angular frequency= w =2pi f= 17.59 rad/s

    C) The amplitude in meters

    At t=o x= 5.2 cm and v = -42 cm/s
    x(t) ...

    Solution Summary

    The expert examines simple harmonic motion on springs.

    $2.19

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