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# Kinetic Energy and Potential Energy

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In this simulation, an object traverses the "hills and valleys" of a frictionless roller coaster in the realm of zero air resistance. You will be asked to find measurements and make calculations concerning total mechanical energy and whether it is conserved. Then you will then make some changes to the global air resistance for this simulation and answer the same questions as you did previously.

I took these calculations from the simulation
Ball Position PE KE TE or E
(-3.61,2.94) t=.10s 0.59J 0.01 0.60
(-.77,.27)
t=.72s 0.05J 0.55 0.60
(.43,1.15)
t=.88s 0.23J 0.37 0.60
(1.93, 2.02)
t=1.12s 0.40J 0.20 0.60
(2.80, 1.44)
t=1.30s 0.29J 0.31 0.60
(3.74, 2.88)
t=2.00s 0.58J 0.02 0.60

Is the total energy (T.E.) conserved in every case (within experimental error)? [If not, where did the missing energy go?] How do I go about figuring this out???

The mass of the ball is changed from 0.01 kg to 1.0 kg
Ball Position PE KE TE or E
(-3.61,2.94) t=.10s 58.89J 1.41 60.30
(-.77,.27)
t=.72s 5.40J 54.89 60.29
(.43,1.15)
t=.88s 23.06J 37.24 60.30
(1.93, 2.02)
t=1.12s 40.47J 19.83 60.30
(2.80, 1.44)
t=1.30s 28.89J 31.41 60.30
(3.74, 2.88)
t=2.00s 57.68J 2.47 60.15

Is the total energy (T.E.) conserved in every case (within experimental error)? [If not, where did the missing energy go?]

The air resistance on the ball changed from 0.0 to 0.05 kg/m*s. The mass is 0.01kg
Ball Position PE KE TE or E
(-3.62,2.95)
t=.10s 0.59J 0.01 0.60
(-1.57, 0.59)
t=.72s 0.12J 0.29 0.41
(0.47, 0.33)
t=.88s 0.07J 0.24 0.31
(0.36, 1.07)
t=1.12s 0.21J 0.03 0.25
(0.48, 1.22)
t=1.30s 0.24J 1.93e^-003 0.25
(-1.38, 0.53)
t=2.00s 0.11J 0.04 0.15

Is the total energy (T.E.) conserved in every case (within experimental error)? [If not where did the missing energy go?]

https://brainmass.com/physics/energy/kinetic-energy-potential-energy-268623

#### Solution Preview

Total Energy = Potential Energy (P.E.) + Kinetic Energy (K.E.) for a moving object.
(where dissipitive ...

#### Solution Summary

The kinetic energy and potential energy is examined.

\$2.19