# Find the wavelength of the electron.

Find the wavelength of an electron with energy E = 2MeV. [Hint: The deBroglie relation lambda = h/p is correct at all energies, but since this energy is relativistic, you will have to use the relation E^2 = (pc)^2 + (mc^2)^2 to find p.]

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#### Solution Preview

E^2 = (pc)^2 + (mc^2)^2

electron mass is 0.5 MeV/c^2

therefore,

2^2 = (pc)^2 ...

#### Solution Summary

This complete solution includes simple calculations.

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