Find the wavelength of an electron with energy E = 2MeV. [Hint: The deBroglie relation lambda = h/p is correct at all energies, but since this energy is relativistic, you will have to use the relation E^2 = (pc)^2 + (mc^2)^2 to find p.]© BrainMass Inc. brainmass.com February 24, 2021, 2:38 pm ad1c9bdddf
E^2 = (pc)^2 + (mc^2)^2
electron mass is 0.5 MeV/c^2
2^2 = (pc)^2 ...
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