See attached diagram.
The diagrams in Figure 9-13 show a brick weighing 24.8 N being released from rest on a 1.00 m frictionless plane, inclined at an angle of 30.0°. The brick slides down the incline and strikes a second brick weighing 37.4 N.
(a) Calculate the speed of the first brick at the bottom of the incline.
(b) If the two bricks stick together, with what initial speed will they move along?
(c) If the force of friction acting on the two bricks is 5.0 N, how much time will elapse before the bricks come to rest?
(d) How far will the two bricks slide before coming to rest?
) Loss of potential energy of brick 1 = (mg)h = 24.8x0.5 = 12.4 J
As the inclined plane is frictionless, no amount of mechanical energy of brick 1 is lost. Whole of the potential energy is converted into kinetic energy. Hence,
½ mv12 = 12.4 where m = mass of the brick 1 = 24.8/9.8 = 2.53 kg
The brick slides down an incline speed is examined. How far the two bricks will slide before coming to rest are determined.