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    A block of mass m is released from rest at a height R above

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    A block of mass m is released from rest at a height R above a horizontal surface.
    The acceleration due to gravity is g. The block slides along the inside of a frictionless circular hoop of radius R.

    A.Which expression would give the speed of the block at the bottom of the hoop and why?

    1.v=mgR
    2.v=mg/2R
    3.v^2=g^2/R
    4.v^=2gR.

    B. What is the magnitude of the normal force exerted on the block by the hoop when the block has reached the bottom?

    See the attached file.

    © BrainMass Inc. brainmass.com June 3, 2020, 7:34 pm ad1c9bdddf
    https://brainmass.com/physics/energy/block-mass-released-rest-height-104608

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    Solution Preview

    From position 1 to 2, potential energy has changed into kinetic energy.
    Position 1: Potential energy = mgR
    Position 2 (bottom of hoop): Kinetic ...

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