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    A small/thin circular conducting disk that can carry total current, as represented by 'I'. The current path is circular at every distance from the center of the disk, and the each circle center is the disk center. Find the magnetic field at the disk center, assuming the current density is:

    1. Constant

    2. Inversely proportional to the distance from the center.

    © BrainMass Inc. brainmass.com October 2, 2022, 4:52 am ad1c9bdddf
    https://brainmass.com/physics/electric-magnetic-fields/magnatic-field-disk-center-466934

    SOLUTION This solution is FREE courtesy of BrainMass!

    ** Please refer to the attachment for the complete solution **

    A small/thin circular conducting disk that can carry total current 'I'. The current path is circular at every distance from the center of the disk, and the each circle center is the disk center. Find the magnetic field at the disk center, assuming the current densit y is:

    1. Constant
    2. inversely proportional to the distance from the center.

    Solution:
    (please see the attached file)
    Case 1: Current density is constant

    The fig. shows a conducting disc of radius R and thickness t carrying the circularly flowing current. Let us consider an annular ring of inner radius r and outer radius r+dr with its center coinciding with the center of the disc. As the current density y is constant, the current density in the annular ring is given by:
    y = k ...(1) where k is a constant

    Area of cross section of the annular ring = t dr ...(2)

    From (1) and (2): Circular current flowing through the annular ring = dI(r) = Current density x Area of cross section of the annular ring = kt dr ...(3)

    Magnetic field at the centre of a current carrying loop is given by: B = μ_0i/2a ...(4)
    where i = Current flowing in the loop, a = Radius of the loop

    Using (4) we determine the magnetic field dB at the centre of the annular ring due to current flowing through it as follows: Radius of the ring = r, Current flowing through it dI = kt dr
    Substituting in (4) we get: dB = (μ_0/2r)(kt dr) = (μ_0kt/2) (1/r) dr ...(5)
    To determine the magnetic field B at the center of the disc due to the current flowing through the complete disc, we integrate (5) in the limits r = 0 and r = R.

    Case 2: Current density is inversely proportional to the distance from the center

    As the current density y is inversely proportional to the distance from the centre, the current density in the annular ring is given by:
    y = k/r ...(1) where k is a constant

    Area of cross section of the annular ring = t dr ...(2)

    From (1) and (2): Circular current flowing through the annular ring = dI(r) = Current density x Area of cross section of the annular ring = kt (1/r) dr ...(3)

    Magnetic field at the centre of a current carrying loop is given by: B = μ0i/2a ...(4)
    where i = Current flowing in the loop, a = Radius of the loop.....

    (Please see the attached file)

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com October 2, 2022, 4:52 am ad1c9bdddf>
    https://brainmass.com/physics/electric-magnetic-fields/magnatic-field-disk-center-466934

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