Electric field due to a charged disc
Not what you're looking for?
A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.90 x 10^-3 C/m^2. Calculate the electric field on the axis of the disk at
(a) 5.0 cm,
(b) 10.0 cm,
(c) 50 cm and
(d) 200 cm from the center of the disk.
Purchase this Solution
Solution Summary
This solution provides a detailed step by step explanation of the given physics problem.
Solution Preview
** Please see the attached file for the complete solution response **
Fig. shows a uniformly charged disc (radius R = 0.35m), with charge density 7.9x10-3 C/m2. Let us consider an annular ring of the disc, co-centric with the disc, having radius r and width dr. Let us consider an infinitesimally small element of the ring between the radius vectors making angles θ and θ+dθ with the X axis. Area of the element = rdθdr. Charge on the element = dq = σ rdθdr where σ is the charge density.
Electric field at point P on the axis of the disc, at a distance s from its centre, due to the element = dE = (1/4ΠЄ0)dq/l2 = (1/4ΠЄ0)σ rdθdr/l2
From the fig. l2 = s2+r2. Hence, dE = (1/4ΠЄ0)σ rdθdr/(s2+r2) .......(1)
The electric field vector dE at ...
Purchase this Solution
Free BrainMass Quizzes
The Moon
Test your knowledge of moon phases and movement.
Intro to the Physics Waves
Some short-answer questions involving the basic vocabulary of string, sound, and water waves.
Variables in Science Experiments
How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.
Basic Physics
This quiz will test your knowledge about basic Physics.
Introduction to Nanotechnology/Nanomaterials
This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.