Three particles are placed in a line. The left particle has a charge of -67 X 10^-6 C, the middle, 45 X 10^-6 C, and the right -83 X 10^-6C. The middle particle is 72cm from each of the others.
a) Find the net force on the middle particle.
b) Find the net force on the right particle.
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Please refer attachment.
As per Coulomb's law electrostatic force acting between two charges q1 & q2 separated by a distance r is given by :
F = (1/4Πε0) q1q2/r2 = (9x109) q1q2/r2 where ε0 is the permittivity of vacuum (or air)
If a charge is subjected to forces by more than one charge, net force experienced by it is given by the vector sum of the forces due to individual charges (superposition principle).
a) The middle charge is subjected to forces due to the charges on either side as follows :
Due to the left charge an attractive force towards left = (9x109)(45x10-6)(67x10-6)/0.722=52.34 N
Due to the right charge an attractive force towards right = (9x109)(45x10-6)(83x10-6)/0.722 = 64.84 N
Net force = 64.84 - 52.34 = 12.5 N towards right
b) The right charge is subjected to forces due to the charges on the left as follows :
Due to the left most charge a repulsive force towards right =(9x109)(83x10-6)(67x10-6)/1.442 = 24.14 N
Due to the middle charge an attractive force towards left = (9x109)(83x10-6)(45x10-6)/0.722 = 64.84 N
Net force = 64.84 - 24.14 = 40.7 N towards left© BrainMass Inc. brainmass.com December 24, 2021, 7:12 pm ad1c9bdddf>