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Coulomb's Law

A H nucleus & a nucleus of yet an unknown atom are stationary at 5.0x10^-10 m apart, Hydrogen atoms mass is mH = 1.7x10^-27kg with an electric charge of e = 1.6x10^-19 C. The Coulomb constant is Ke = 9.0x10^9 Nm^2 C^-2 and that the gravitational constant is G = 6.7x10^-11 N m^2 kg^-2.

Is the force between the hydrogen and the unknown atom is attractive or repulsive.

What is the electric charge of the unknown atom in coulombs with notation and as a whole number integer of the multiple of the charge of the H nucleus, e. Assumption is that the whole number is the atomic number of the unknown nucleus such as protons within it.

The magnitude of the gravitation force between the H nucleus and the unknowns is 9.3x10^-45 N. is this force attractive or repulsive. What is the mass of the unknown nucleus that is need to give a force of the magnitude in kg and notation. What is the mass as a whole number of a H nucleus mH with the assumption that this whole number is the mass number of the unknowns nucleus e.g. total number of nucleons.

And what is the isotope symbol for the unknown nucleus and what element does it belong to.

Solution Preview

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A H nucleus & a nucleus of yet an unkown atom are stationary at 5.0x10-10 m apart. Hydrogen nucleus mass is mH = 1.7x10-27kg with an electric charge of e = 1.6x10-19 C. The Coulomb constant is ke = 9.0x109 Nm2 C-2 and that the gravitational constant is G = 6.7x10-11 N m2 kg-2.

The magnitude of electric force between the hydrogen nucleus and the unknown nucleus is 5.5x10-9 N. Is this force between the hydrogen and the unkown nucleus attractive or repulsive?

What is the electric charge on the unkown nucleus in coulombs expressed in scientific notation. Express this charge as a whole ...

Solution Summary

Step-by-step solution using Coulomb's Law is provided. The force between a hydrogen nucleus and an unknown nucleus is discussed.

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