1. Four charges are held together in place as shown (see attachment). Q1 = +30 micro C and Q2 = Q3 = Q4 = +15 micro C. Determine the magnitude and direction of the total force on charge 2.

1a. Draw all force vectors on charge 2 due to every other charge. Label each vector accordingly with two subscripts. Draw the vectors so that the tail of each vector originates on the charge.

1b. Determine the magnitude of each force listed below:

F21: ____________________

F23: ____________________

F24: ____________________

1c. List the x and y components of Fnet on charge 2 in terms of unit vectors (i and j):

Fnet = __________ i + _____________ j

Determine the magnitude of Fnet:

Fnet = ___________________

1d. Determine the direction of Fnet on charge 2 by solving for angle theta, which is measured counterclockwise from the +x direction. Draw a sketch of Fnet originating on charge 2 below, showing the angle theta. The coordinate axis is shown.

Step by step solution provided. The expert determines the force on a charge due to three other charges. Vectors according to subscripts are determined.

... 9. What does it mean when you calculate a negative force using Coulomb's Law? When are electrostatic forces attractive? When are they repulsive? ...

... of the electrostatic force that one charge exerts on the other. Is the force attractive or repulsive? Solution: 7.5 nC 1.8 m 4.2 nC. Applying Coulomb's law we ...

... As we had learnt in electrostatics, as per Coulomb's law the force ... The process of electrolysis is described by Faradays laws of electrolysis as follows : ...

... Where k is the Coulomb constant. ... Gauss law simply states that the flux through any enclosed volume is proportional to the total net charge enclosed in the ...

... In the gravitational case gamma = -MmG and in the electrostatic case gamma ... 1) Both the Coulomb law and gravitational forces lead to potential energies of the ...

... upon the earlier works of Coulomb, Gauss and ... out certain discrepancies in the Ampere's law and proposed ... Gauss' equation of electrostatics: As per Gauss theorem ...

... charges. By Coulomb's law : F = [kQ(-RQ/D)]/(D- R2/D)2 + kQ(VR/k)/D2. ... This is a good application of method of images of electrostatics. The ...

... is equivalent to flow of 1-coulomb charge per ... on resistivity & resistance, ohm's law, resistances in ... in a conductor: We have learnt in electrostatics, a charge ...