Two point charges have a total charge of 590 uC. When placed 1.30 m apart, the force each exerts on the other is 22.8 N and is repulsive. What is the charge on each?

Solution Preview

The Coulomb force is: F = kq^2 / r^2,
and the total charge is: 2q = Q.

So we ...

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... (a) By Coulomb's law, the electric field of the point charge is 4.0 × 10−6 C 4.0 µ C ( ) ( ) Q E = k 2 = 9 × 109 N ⋅ m 2 ⋅ C −2 = 9 ×109 N ⋅ m 2...

... By Coulomb's law : F = [kQ(-RQ/D)]/(D- R2/D)2 + kQ(VR/k)/D2. ... the imaginary charge q we can have the net potential due to the two charges at any point on the ...

... Four questions regarding the Coulomb's law are answered. In all question, a point charge is placed together with one (or two) other point charges in a straight ...

... d) the charges repelled the compass via Coulomb's Law (e) none ...2. A long straight wire carrrying a current of 4.00 A ... It is found that at some point P the field ...

... Applying Coulomb's law we get: Force of repulsion between the two charges... Problem 3. A uniform electric field of magnitude 375 N/C pointing in the ...

... Gauss law simply states that the flux through any enclosed volume is ... Where k is the Coulomb constant. ... 10 7 ⎟i ⎜ r ⎟jj ⎜r ⎝2 r1 ⎠ ⎝ 3 r4 ⎠ C. ...

... E(r) = rho/(3 epsilon_0) r (2). ... the sphere and we see that E(r) is given by Coulomb's law. ... things can be made unambiguous by defining the reference point to be ...

... Give electric fields in N/C and charges in Coulombs. ... Gauss' law to determine the electric field E at r = 2R2 = 2 x 20.41 = 40.82 mm Gauss' law: ∫E.ds ...