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    A phone line 2.0 m in diameter and 0.5 km long is stretched 0.5 m by a force of 4000 N. Determine:
    1. the stress on the wire
    2. the strain on the wire
    3.Young's modulus for the cable material.

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    Solution Preview

    d=diameter of line= 2 m
    Therefore cross sectional Area of line =pi d^2/4= 3.1416 m^2

    1. the stress on the wire ...

    Solution Summary

    Calculates the stress, the strain and the Young's modulus.