A phone line 2.0 m in diameter and 0.5 km long is stretched 0.5 m by a force of 4000 N. Determine:
1. the stress on the wire
2. the strain on the wire
3.Young's modulus for the cable material.
d=diameter of line= 2 m
Therefore cross sectional Area of line =pi d^2/4= 3.1416 m^2
1. the stress on the wire ...
Calculates the stress, the strain and the Young's modulus.