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A phone line 2.0 m in diameter and 0.5 km long is stretched 0.5 m by a force of 4000 N. Determine:
1. the stress on the wire
2. the strain on the wire
3.Young's modulus for the cable material.

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Solution Summary

Calculates the stress, the strain and the Young's modulus.

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d=diameter of line= 2 m
Therefore cross sectional Area of line =pi d^2/4= 3.1416 m^2

1. the stress on the wire ...

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