A tank of oil, p=670kg/m^3, develops a leak. The leak is 6m below the open surface of the tank.
B. In time the leak will be 5m below the surface of oil in the tank. What will be the volume flow rate at that time?
C. How much oil by volume has been lost from the tank between A and B? Justify answer please.
a) Potential energy at the top of the tank = pi * (1)^2 *6 * 670 * g * 6
When the oil flows through the hole, all these is converted into Kinetic energy
= 1/2 * pi * 1^2 *6 * ...
The solution shows all the calculations with explanations to answer the problem.