Working with Thevenin's theorem
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Please check my work and if incorrect give me the correct answer
Please refer to the problem stated in the attached file.
(For the circuit shown below, beta = 80. What is the value of Ic?)
My solution is:
Beta=80
Vbe=.7
Solve for Ic
Step one:
Vbb=+15*Rb2/(Rb1+Rb2)=15*50/(100+50)=+5
step two
Rbb=Rb1//Rb2=(100*50)/(100+50)=33.33
Ie=(Vbb-Vbe)/Re+[Rbb/(Beta+1)
=(5-.7)/3+(33.3/81)=4.3/3.41=1.26mA
Ib=Ie/(Beta=1)=1.26/81=.01557mA
Vb=Vbe+IeRe=.7+(1.26*3)
alpha=80/81=.9877
Ic=alphaIe=.9877*1.26=1.244
Answer is A
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The base is connected to a voltage divider circuit, the current through those resistors is
I1 = 15/(100+50)*10^3 = 0.0001 A
Voltage across, R_B2,
Vbb = 0.0001 * ...
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