For the circuit shown in the figure (please see attachment) both meters are idealized, the battery has no appreciable internal resistance, and the ammeter reads 1.85A. Determine E and voltage drop across 45 ohm resistor.
15 ohm and 10 ohm resistors are in series, hence equivalent to 25 ohm.
Three parallel resistances 25 ohm, 15 ohm and 25 ohm have an equivalent resistance R is given by : 1/R = 1/25 + 1/15 + ...
Step by step solution provided.