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For the circuit shown in the figure (please see attachment) both meters are idealized, the battery has no appreciable internal resistance, and the ammeter reads 1.85A. Determine E and voltage drop across 45 ohm resistor.

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15 ohm and 10 ohm resistors are in series, hence equivalent to 25 ohm.

Three parallel resistances 25 ohm, 15 ohm and 25 ohm have an equivalent resistance R is given by : 1/R = 1/25 + 1/15 + ...

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